Question

Chose the equation that represents the line that passes through the point (2,6) and has a slope of -5

Answer 1

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (2, 6).

Substitute:

`y-6=-5(x-2)`

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

Convert:

`y-6=-5(x-2)` use the distributive property a(b + c) = ab + ac

`y-6=-5x+(-5)(-2)`

`y-6=-5x+10` add 6 to both sides

`y=-5x+16`

The standard form of an equation of a line:

`Ax+By=C`

Convert:

`y=-5x+16` add 5x to both sides

`5x+y=16`