Question

Write an equation of the line that passes through the point (-2,-4) with slope -6

Answer 1

`\boxed{y = -6x - 16}`

Explanation:

The point-slope formula for a straight line is

`y - y_(1) = m(x - x_(1))}`

x₁ = -2; y₁ = -4; m = -6

Substitute the values

`\begin{array}{rcl}y - (-4) & = & -6(x - (-2))\\y + 4 & = & -6(x + 2)\\y + 4 & = & -6x - 12)\\y & = & -6x - 16\\\end{array}\\\text{The equation for the line is $\boxed{\mathbf{y = -6x - 16}}$}`

The diagram shows the graph of the equation with slope -6 passing through (-2,--4).