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Answer:
<3~(B) (C) (F)~<3
Explanation:
as seen in the screenshot <3333^v^
proofs:
We want to prove
Let . By definition is the set that contains the elements of and the elements of . Then must be in . As was arbitrary, we conclude that .
This proof is analogous to the previous one. In fact, this result is the same result as the previous one.
Let . By definition of the intersection should be in and also in . Then, we already saw that . As was arbitrary we can conclude that .
This is the same result as the previous one. There is no need to prove it anymore, but if you wish, you can reply the exact same proof.