asked 91.6k views
2 votes
A length of aluminum wire has a resistance of 14.0 Ω at 36.0°C. When the wire is warmed in an oven and reaches thermal equilibrium, the resistance of the wire increases to 31.1 Ω. (a) Neglecting thermal expansion, find the temperature of the oven.

1 Answer

5 votes

Answer:

The temperature of the oven is: T2= 309.86 ºC.

Step-by-step explanation:

α= 0.00446 1/ºC

R1= 14 Ω

R2= 31.1Ω

T1= 36ºC

R2= R1 * {1+α * (T2-T1) }

T2= {[(R2/R1)-1] * 1/α} + T1

T2= 309.86ºC

answered
User Dedman
by
8.6k points