Question

Kim ate 3⁄10 of a bag of potato chips; Sandy ate 3⁄7 of a bag; and Jeff ate 3⁄9 of a bag. Who ate the most, Kim, Jeff, or Sandy?

Answer 1

you can always, put all fractions with the same denominator, and check whose numerator is the largest, we can do so by getting the LCD in this case it'll simply be the product of all three denominators, 10*7*9, and then multiply top and bottom of each by that quotient of the LCD and denominator.

`\bf \stackrel{\stackrel{\textit{using an}}{\textit{LCD of}}}{630}~\hfill \underset{KIM}{\stackrel{630/ 10=63}{\cfrac{3}{10}\cdot \cfrac{63}{63}\implies \boxed{\cfrac{189}{630}}}}~\hfill \underset{\underline{SANDY}}{\stackrel{630/ 7=90}{\cfrac{3}{7}\cdot \cfrac{90}{90}\implies \boxed{\cfrac{270}{630}}}}~\hfill \underset{JEFF}{\stackrel{630/ 9=70}{\cfrac{3}{9}\cdot \cfrac{70}{70}\implies \boxed{\cfrac{210}{630}}}}`

Answer 2

Sandy, she ate 42.85% of the bag.

Explanation:

Divide the numerator by the denominator for each person.

Kim - 3÷10= 0.3 (30%)

Sandy - 3÷7= 0.4285714286 (42.85%)

Jeff - 3÷9= 0.333333 (33.33%)

*Remember when dividing fractions 1=100%, ie, 4/2= 200%, 5÷10= 50%*