Question

Let f(x)= 3x-2 and g= {(0,2), (1,4), (-2,3), (-1,2)} then evaluate (3f+g)(0)

Answer 1

-4

Explanation:

`(3f+g)(0)=3f(0)+g(0)\\\\f(x)=3x-2\\f(0)-\text{put}\ x=0\\f(0)=3(0)-2=0-2=-2\\3f(0)=3(-2)=-6\\\\g(x):\{\bold{(0,\ 2)},\ (1,\ 4),\ (-2,\ 3),\ (-1,\ 2)\}\to g(0)=2\\\\(3f+g)(0)=-6+2=-4`