One integer is 1/3 times another. The sum of their squares is 90. What are the two integer?

Question

asked Nov 13, 2020 154k views

1 Answer

Charles Finkel · Answer 1 · 2020-11-17T07:13:54+0000

Hence, the two integers could be:

3 and 9

0R

-3 and -9

Let the two integers be denoted by a and b.

It is given that:

One integer is 1/3 times another.

i.e. let

a=(1)/(3)b

i.e.

b=3a

Also,

The sum of their squares is 90.

i.e.

$a^2+b^2=90\\\\i.e.\\\\a^2+(3a)^2=90\\\\i.e.\\\\a^2+9a^2=90\\\\i.e.\\\\10a^2=90\\\\i.e.\\\\a^2=9\\\\i.e.\\\\a=\pm 3$

Hence, when a=3 we have:

b=9

and when,

a=-3

then b=-9