Question

Help with inverse please​

Answer 1

as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables, and then solve for "y".

`\bf y = 4x^2-8\implies \stackrel{\textit{quick switcheroo}}{\underline{x} = 4\underline{y}^2-8}\implies x+8=4y^2\implies \cfrac{x+8}{4}=y^2 \\\\\\ \sqrt{\cfrac{x+8}{4}}=y\implies \cfrac{√(x+8)}{√(4)}=y\implies \cfrac{√(x+8)}{2}=\stackrel{f^(-1)(x)}{y}`