Answer:
Explanation:
Sounds as tho' there were several answer choices. You're expected to share them.
To graph f(x)=5(2)^x, first graph g(x)=(2)^x, the basic base-2 exponential function. The y-intercept is (0, 1) and the horizontal intercept is y = 0 (the x-axis). The graph begins in Quadrant II and continues in Quadrant I with no upper limit to g(x).
Once you've graphed that, "stretch" this graph vertically by a factor of 5.
The vertical intercept is now (0, 5).