Question

If you are given the graph of h(x)=log(6)x, how could you graph m(x)=log(6)(x+3)? Translate each point of the graph of h(x) 3 units up. Translate each point of the graph of h(x) 3 units down. Translate each point of the graph of h(x) 3 units right. Translate each point of the graph of h(x) 3 units left.

Answer 1

Last option (D) Translate each point of the graph of h(x) 3 units left.

Answer 2

Last option: Translate each point of the graph of h(x) 3 units left.

Explanation:

There are some transformations for a function f(x). The following is one of these transformations:

If
`f(x+k)`, then the function is shifted "k" units to the left.

Given the function
`h(x)=log_6(x)` and the function
`m(x)=log_6(x+3)`, you can notice that the function m(x) is the function h(x) but shifted left 3 units.

Therefore, you could graph the function m(x) by translating each point of the graph of the function h(x) 3 units left.

This matches with the last option.