Question

If given both the speed of light in a material and an incident angle. How can you find the refracted angle?

Answer 1

`r = Sin^(-1)\left ( (v Sini)/(c) \right )`

Step-by-step explanation:

Let the speed of light in vacuum is c and the speed of light in medium is v. Let the angle of incidence is i.

By using the definition of refractive index

refractive index of the medium is given by

n = speed of light in vacuum / speed of light in medium

n = c / v ..... (1)

Use Snell's law

n = Sin i / Sin r

Where, r be the angle of refraction

From equation (1)

c / v = Sin i / Sin r

Sin r = v Sin i / c

`r = Sin^(-1)\left ( (v Sini)/(c) \right )`