Question

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Answer 1

Answer: b) 18.37

Explanation:

Since the intial t-value is 1960 and the final t-value is 1990, then t = 30

`P(30)=(100)/(1+400\cdot e^(-0.15(30)))\\\\\\.\quad =(100)/(1+400\cdot e^(-4.5))\\\\\\.\quad =(100)/(1+400(0.0111))}\\\\\\.\quad =(100)/(1+4.4436)}\\\\\\.\quad =(100)/(5.4436)}\\\\\\.\quad =\boxed{18.37}`