Question

5. Write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3)

Answer 1

y = -5x - 27

Explanation:

First and foremost, parallel lines have SIMILAR RATE OF CHANGES [SLOPES], so we keep the -5. Moving forward, we simply plug the coordinate into the Slope-Intercept Formula, y = mx + b --> 3 = -5[-6] + b. Our y-intercept is [0, -27], therefore our parallel equation is y = -5x - 27.