The equation 3x2 = 6x - 9 has two real solutions True False

Question

asked Feb 5, 2020 47.0k views

1 Answer

BiigNiick · Answer 1 · 2020-02-09T02:11:46+0000

Answer: FALSE

Explanation:

The first step is to rewrite the equation in the form
ax^2+bx+c=0 , then:

$3x^2 = 6x - 9\\3x^2-6x +9=0$

Now, we need to calculate the Discriminant with this formula:

D=b^2-4ac

We can identify in the given equation that:

$a=3\\b=-6\\c=9$

Then, we only need to substitute these values into the formula:

D=(-6)^2-4(3)(9)

D=-72

Since
D<0 then the equation has no real solutions.