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X^2+x+3 factor the polynomial

1 Answer

2 votes

Answer:

x = -1/2 + (i/2)√11 and x = -1/2 - (i/2)√11

Explanation:

This polynomial is a quadratic. Its coefficients are a = 1, b = 1 and c = 3.

Thus, the discriminant b^2-4ac is 1^2 - 4(1)(3), or 1 - 12, or -11.

Because the discriminant is negative, the roots are complex.

The roots are:

-1 ±√(-11) -1 ±i√11

x = --------------- = ----------------, so x = -1/2 + (i/2)√11 and x = -1/2 - (i/2)√11

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User Kidjan
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