Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. –2.2, –11.8, –19.8 –3, –11.8, –25 –3, –9.6, –22.8 0, –6.6, –19.8

Question

asked Apr 9, 2020 20.4k views

1 Answer

Halirutan · Answer 1 · 2020-04-15T11:41:46+0000

Answer:

–3, –9.6, –22.8

Explanation:

Given rule is:

A(n) =-3+(n-1)(-2.2)

So,

For first term:

$A(1) =-3+(1-1)(-2.2)\\A(1) = -3 +0\\= 0$

For fourth term:

$A(4) =-3+(4-1)(-2.2)\\=-3+(3)(-2.2)\\=-3+ (-6.6)\\=-3-6.6\\= -9.6$

For tenth term:

$A(10) =-3+(10-1)(-2.2)\\=-3+(9)(-2.2)\\=-3+ (-19.8)\\=-3-19.8\\= -22.8$

The first, fourth and tenth terms are -3, -9.6 and -22.8 respectively.

So, third option is correct ..