Question

Triangle XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z'. What is the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

Answer 1

5

Explanation:

Answer 2

The distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′ is equal to
`5\ units`

Explanation:

we know that

To find the distance, apply the Pythagoras Theorem

Let

x ----> the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

`x=\sqrt{4^(2)+3^(2)} \\ \\x=√(25)\ units\\ \\x=5\ units`