Question

Calvin evaluated -2/3 *5 1/6 using the steps below.

Answer 1

The error is identified in C. In step 2, he confused the multiplication and addition signs.

What is Calvin's error?

In step 2, he confused the multiplication and addition signs.

Step 1: -2/3 x (5 + 1/6)

Step 2: (-2/3 × 5) + (-2/3 × 1/6)

Step 3: -10/3 + -12/18

Step 4: -10/3 - 2/3

= (-10-2)/3

= -12/3

= -4

Therefore,

Calvin's answer should be negative 4

Complete Questiion:

Calvin evaluated -2/3 x 5 1/6 using the steps below.

Step 1: -2/3 x (5 + 1/6)

Step 2: (-2/3 + 5)x(-2/3 + 1/3)

Step 3: 4 1/3 x -1/3

Step 4: -2 1/6

Which describes Calvin’s error?

In step 1, he incorrectly broke up 5 1/6.

In step 2, he distributed the -2/3 instead of the 5.

In step 2, he confused the multiplication and addition signs.

In step 3, he computed the addition and multiplication incorrectly

Answer 2

For this case we have to evaluate the following expression,

`- \frac {2} {3} * 5 \frac {1} {6}`

We must follow the steps below:

We convert the mixed number into a fraction:

`- \frac {2} {3} * \frac {6 * 5 + 1} {6} =\\- \frac {2} {3} * \frac {31} {6} =`

We multiply the fractions, taking into account that:

`- * + = -\\- \frac {2 * 31} {3 * 6} =\\- \frac {62} {18} =`

We simplify:

`- \frac {31} {9}`

We convert to mixed number:

`-3 \frac {4} {9}`

Answer:

`-3 \frac {4} {9}`