Question

What is the y- value of the vertex of 4c^2+8x-8

Answer 1

a =4 b=8 c=-8

y-value of vertex =

ah^2 + bh + c

where h = -b/2a

h= -8/8 =-1

y-value of vertex =

4(-1)^2 + 8*-1 -8

4 -8 -8

y value of vertex = -12

Explanation: