Question

This shouldn't be too difficult i just don't know what i'm doing please help

Write the expression below as a function of cos only.

sin²x/1+cos x

Answer 1

`(1-cos^2x)/(1+cosx)`

Explanation:

We are given the expression

`(sin^2x)/(1+cosx)`

We can use the Pythagorean identity of
`sin^2x+cos^2x=1` when solved for
`sin^2x=1-cos^2x`

Now we can substitute in our identity for
`sin^2x`

`(1-cos^2x)/(1+cosx)`