Question

Find the product:

(5/3)(2/3)(21/1)

I preset 21, but please help!

Answer 1

Final answer is
`(70)/(3)`.

Explanation:

Given expression is :

`\left((5)/(3)\right)\cdot\left((2)/(3)\right)\cdot\left((21)/(1)\right)`

Now we need to find their product. In other words simplify it

We can multiply numerator with numerator. Then denominator with denominator

`\left((5)/(3)\right)\cdot\left((2)/(3)\right)\cdot\left((21)/(1)\right)`

`=(5\cdot2\cdot21)/(3\cdot3\cdot1)`

`=(210)/(9)`

`=(70)/(3)`

So the final answer is
`(70)/(3)`.

Answer 2

Answer:
`(70)/(3)`

Explanation:

Given a fraction
`(a)/(b)` and a fraction
`(c)/(d)`, you can find the product by multiplying the numerator of the first fraction by the numerator of the second fraction and the denominator of the first fraction by the denominator of the second one:

`(a)/(b)*(c)/(d)=(ac)/(bd)`

Therefore, knowing this you can find the product of the fractions
`((5)/(3))((2)/(3))((21)/(1))`:

`((5)/(3))((2)/(3))((21)/(1))=(5*2*21)/(3*3*1)=(210)/(9)`

And finally you need to reduce the fraction:

`=(70)/(3)`