Answer:
upper left
Explanation:
The generic equation for a circle centered at (h, k) with radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Comparing that equation to the one you have, you can see that ...
-h = 0
-k = +3
r^2 = 9
Then you have (h, k) = (0, -3) and a radius of 3.
The circle has its center on the y-axis 3 units below the x-axis and just touches the x-axis. This is a description of the graph at upper left.