Question

What are the vertical and horizontal asymptotes for the function f(x)= x^2+x-6/x^3-1?

a) vertical asymptote: x = 1
horizontal asymptote: none

b) vertical asymptote: x = 1
horizontal asymptote: y = 0

c) vertical asymptote: x = –2, x = 3
horizontal asymptote: y = 0

d) vertical asymptote: x = –2, x = –3
horizontal asymptote: none

Answer 1

b

Explanation:

Answer 2

Option B

Explanation:

Given

f(x)= (x^2+x-2)/(x^3-1)

For vertical asymptotes we have to put the denominator of the function equal to zero:

x^3-1=0

x^3=1

So,

x=1

As the degree of denominator is greater than the degree of numerator, there will be only horizontal asymptote which will be y=0 because all the y values will be dragged down to the x-axis.

So the horizontal asymptote: y=0

And Vertical asymptote: x =1