Question

In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 56.8 minutes. What is the frequency of this oscillations?

Answer 1

Answer:
`2.9(10)^(-4) Hz`

The frequency is defined as the inverse of the period
`T` (time):

`f=(1)/(T)` (1)

And according to the International Units System its unit is Hertz (
`Hz=1/s`).

This means we have to convert this quantity given in minutes to seconds before solving the equation:

`T=56.8 min.(60s)/(1min)=3408s` (2)

Substituting (2)in (1):

`f=(1)/(3408s)`

Finally:

`f=0.00029Hz=2.9(10)^(-4) Hz`