What is the magnitude of the resultant vector of z-y?

Question

asked Aug 15, 2020 194k views

1 Answer

Roman Timushev · Answer 1 · 2020-08-21T23:28:32+0000

For this case what we should do is take into account the following vectors:

$z = (-1,5,3)\\y = (- 6.2, -1)$

We must find the following subtraction of vectors:

z-y = (- 1,5,3) - (- 6,2, -1)

Subtracting component to component we have:

z-y = ((- 1 + 6), (5-2), (3 + 1))

By writing we have:

z-y = (5,3,4)

Then the module of the resulting vector is given by:

$| z-y | = \sqrt {5 ^ 2 + 3 ^ 2 + 4 ^ 2}$

Rewriting we have:

$| z-y | = \sqrt {50}\\ | z-y | = \sqrt {2 * 25}\\ | z-y | = 5\sqrt {2}$

Answer:

The module of the resulting vector is given by:

$| z-y | = 5\sqrt {2}$

option B