Question

Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x.

Answer 1

-10x^2-3x+4

Hope this helps

Answer 2

quotient is
`10x^2+3x-4`

Explanation:

`(-40x^3-12x^2+16x)/(-4x)`

To find the quotient we divide each term by -4x

`(-40x^3)/(-4x) =10x^2`

Negative and negative becomes positive.

`(-12x^2)/(-4x) =3x`

`(-16x)/(-4x) =-4`

`(-40x^3-12x^2+16x)/(-4x)=10x^2+3x-4`