Question

Factor
(3c–5)^2–16c^2

Answer 1

Here is your answer

`{(3c - 5)}^(2) - {16c}^(2)`

`= {(3c - 5)}^(2) - {(4c)}^(2)`

`using \: identity \\ {a}^(2) - {b}^(2) = (a + b)(a - b)`

`(3c - 5 + 4c)(3c - 5 - 4c)`

`(7c - 5)( - c - 5)`

HOPE IT IS USEFUL