Question

(x-p)^2=p
-9+12x-6x^2=0

Answer 1

Explanation:

Hello

(x-p)^2=p (I don’t understand)

-9+12x-6x^2=0

6x^2 - 12x + 9 = 0

3(2x^2 - 4x + 3) = 0

2x^2 - 4x + 3 = 0

`\Delta = (-4)^(2) - 4 * 2 * 3 = 16 - 24 = -8` < 0 so no solutions