Question

Evaluate i^31 please help

Answer 1

`{i}^(31) = - i`

Step-by-step explanation

We want to evaluate

`{i}^(31)`

Use indices to rewrite the expression as:

`= {i}^(30) * i`

We know that

`{i}^(2) = - 1`

So we rewrite the expression to obtain;

`= ({ {i}^(2)) }^(15) * i`

This gives us;

`= {( - 1) }^(15) * i`

This simplifies to

`= - 1 * i`

`= - i`