asked 175k views
5 votes
A 1.3 g sample of a substance is heated from 0°C to 45°C and is found to have absorbed 45 j of heat. What is the specific heat of this substance?

asked
User Flori
by
8.1k points

1 Answer

3 votes

Q=mcat

45=(1.3)(c)(45)

45=58.5c

.769=c

~.77

The answer is .77

answered
User Alvis
by
7.7k points
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