Question

What is the center of the circle given by the equation (x−6)2+(y+3)2=72? A. (-6, 3) B. (-3, 6) C. (6, -3) D. (6, 7)

Answer 1

The center of the circle is the x and y in the equation.

To find the center you need to solve for x and Y when the equations inside parenthesis are set to zero.

(x-6)=0

x = 6

(y+3)=0

y = -3

The center of the circle is (6,-3)