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Evaluate each log without a calculator


log_(4) (1)/(16)


log_(2)\sqrt[5]{32}

1 Answer

6 votes

QUESTION 1

The given logarithmic expression is


\log_4((1)/(16))

We rewrite
(1)/(16) in the index form to base 4.

This implies that;


\log_4((1)/(16))=\log_4(4^(-2))

We now apply the power rule:
\log_a(m^n)=n\log_a(m^n).


\log_4((1)/(16))=-2\log_4(4)

Recall that logarithm of the base is 1.


\log_4((1)/(16))=-2(1)


\log_4((1)/(16))=-2

QUESTION 2

The given logarithm is;


\log_2(\sqrt[5]{32})


\log_2(\sqrt[5]{2^5})

This is the same as;


\log_2(2^{5* (1)/(5)})


\log_2(2^(1))


\log_2(2)=1

answered
User GertVdE
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