Question

I REALLY NEED SOMEONES HELP ON THIS PLEASE!! I NEED THIS DONE TODAY!

Error analysis: Describe the error in the way the product of the two binomials is set up and/or solved. Please be specific. (Image is listed below)

Solve the problem in the question above correctly. Please show your work!

Answer 1

`\huge\boxed{\text{The $5$ needs to be negative.}}`

Since the first binomial is
`(x-5)`, the
`5` is negative and must be that way when using the table.

Here's the corrected table:

`\begin{array}c\multicolumn{1}{c}{}&\multicolumn{1}{c}{3x}&\multicolumn{1}{c}{1}\\\cline{2-3}x&3x^2&x\\\cline{2-3}-5&-15x&-5\\\cline{2-3}\end{array}\\\\\\3x^2+x-15x-5\\3x^2-14x-5`