Question

On a coordinate grid, a park is located at (3,0) and the pool is located at (-3,3). If the tennis courts are the midpoint between the park and the pool, what is the approximate distance from the pool to the tennis courts? (Note: 1 unit equals 1 mile)

A) 1.5 miles
B) 2.79 miles
C) 3.35 miles
D) 4.74 miles

Answer 1

I think c if not sorry have a good day

Answer 2

The approximate distance from the pool to the tennis courts is:

C) 3.35 miles

Explanation:

It is given that:

On a coordinate grid, a park is located at (3,0) ande the pool is located at (-3,3).

The tennis courts are the midpoint between the park and the pool.

This means that the distance from the pool to the tennis court is half the distance between the pool and the park.

The distance between pool and park is calculated by using the distance formula as follows:

`Distance\ between\ pool\ and\ park=√((3-(-3))^2+(0-3)^2)\\\\Distance\ between\ pool\ and\ park=√((3+3)^2+(-3)^2)\\\\i.e.\\\\Distance\ between\ pool\ and\ park=√(6^2+3^2)\\\\i.e.\\\\Distance\ between\ pool\ and\ park=√(36+9)\\\\i.e.\\\\Distance\ between\ pool\ and\ park=√(45)\\\\i.e.\\\\Distance\ between\ pool\ and\ park=3√(5)\\\\i.e.\\\\Distance\ between\ pool\ and\ park=6.7082\ units`

Hence,

`Distance\ from\ pool\ to\ tennis\ court=(6.7082)/(2)\\\\i.e.\\\\Distance\ from\ pool\ to\ tennis\ court=3.3541\ units`

Now, it is given that:

1 unit= 1 mile

Hence, 3.3541 unit=3.3541 miles.

Hence, the answer is: Option: C