Question

What are the zeros of g(x)=(3x-1)(2x+5)(7x-14)^2

ANSWER ASAP BY THE END OF THE DAY WITH THE WORK. PLZ!

Answer 1

see explanation

Explanation:

To find the zeros equate g(x) to zero, that is

(3x - 1)(2x + 5)(7x - 14)² = 0

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x =
`(1)/(3)`

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = -
`(5)/(2)`

(7x - 14 )² = 0 ⇒ 7x - 14 = 0 ⇒ x = 2 with multiplicity 2