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What is the equation of the horizontal asymptote

f(x)=4 (5/2)^x+

high school question

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User Vee
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1 Answer

2 votes

Answer:

y = 0

Explanation:

If the exponent is a negative number n, f(x) = 4(5/2)⁻ⁿ =4/(5/2)ⁿ

As the denominator becomes large, ƒ(x) ⟶ 0.

The equation for the horizontal asymptote is y = 0.

What is the equation of the horizontal asymptote f(x)=4 (5/2)^x+ high school question-example-1
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User Vemka
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