Answer:
D. x, x + 1, x + 2
Explanation:
We have been given four choices of expressions 
A. x – 1, x, x + 1 
B. x + 1, x, x + 2 
C. x, x + 2, x + 4 
D. x, x + 1, x + 2
Now we need to find about which expression lists the three consecutive integers starting with a number x.
We know that consecutive integers can be found by adding 1.
Given that starting integer is x
then 2nd consecutive integer = x+1
then 3rd consecutive integer = x+1+1=x+2
Hence correct choice is 
D. x, x + 1, x + 2