Question

3. A boat at sea is being moved by the ocean current at 5 metres/minute directly to the east. At the same time it is being moved directly to

the north at 3 metres/minute by a strong wind. Determine the magnitude and direction of the boat's overall velocity.

Answer 1

Step-by-step explanation:

A boat at sea is being moved by the ocean current at 5 metres/minute directly to the east.

At the same time, it is being moved directly to the north at 3 metres/minute by a strong wind.

We need to find the magnitude and direction of the boat's overall velocity.

As both velocities are moving perpendicular to each other. The resultant velocity is given by :

`v=√(5^2+3^2) \\\\=√(25)\\\\=5\ \text{metres/minute}`

For direction,

`\tan\theta=(v_y)/(v_x)\\\\=\frac{3}5{}\\\\\theta=\tan^(-1)(\frac{3}5{})\\\\=30.96^(\circ)`

Hence, this is the required solutin.