Question

Write expression as one circular function ​

Answer 1

`\cos^2 x`

Explanation:

`(\cos^2 x \sin^2 x)/(\tan^2 x(1 - \sin^2 x)) =`

`= \frac{\cancel{\cos^2 x} \sin^2 x}{\tan^2 x\cancel{\cos^2 x}}`

`= (\sin^2 x)/(\tan^2 x)`

`= (\sin^2 x)/((\sin^2 x)/(\cos^2 x))`

`= \sin^2 x * (\cos^2 x)/(\sin^2 x)`