Question

Identify the phase shift of each function. Describe each phase shift ( use a phrase like 3 units to the left):

Answer 1

ANSWER

Phase shift: 2 units to the right.

Step-by-step explanation

Comparing


`y = \cos(3x - 6)`

to


`y=A\cos(Bx-C)+D`

The phase shift is the same as the horizontal translation.

The horizontal shift is


`(C)/(B) = (6)/(3 ) = 2`

units to the right.

Answer 2

Answer;

The phase shift will be 2 units to the right

Step-by-step explanation:

The Phase Shift is how far the function is shifted horizontally from the usual position.

Therefore; in a function in the form;

y = A sin(B(x + C)) + D

The phase shift is C (positive to the left)

The function;

y = cos (3x - 6)

We could write the function in the form of y = A sin(B(x + C)) + D

We have; y = cos (3x - 6)

we get y = Cos (3(x - 2)

Therefore; the phase shift will be 2 units to the right.