What is the enthalpy of 2NO2(g) yields N2(g) + 2O2 (g)

Question

asked May 26, 2020 128k views

2 Answers

Artur Sapek · Answer 1 · 2020-05-31T23:32:40+0000

Answer:

-67.8 kJ

Step-by-step explanation:

2NO₂(g) ⇌ N₂(g) + 2O₂(g)

ΔH°f/kJ·mol⁻¹: +33.9 0 0

ΔH°r = ΣΔH°f(products) - ΣΔH°f(reactants)

= 0 - 2(33.9)

= -67.8 kJ