Answer:
The length approximately is 62.36 meters tall. 
Explanation:
In this figure DF is hypotenuse , DE is perpendicular and FE is base 
So we will use TanQ = perpendicular where Q is theta which is 28 here, 
Base, 
TanQ= DE/ FE, here DE is 33 
Tan (28) = 33/FE 
0.53 = 33/FE 
FE = 33/0.53 
FE = 62.26 
Building is 62.36 m tall