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Use the distributive property to factor the expression. 2yz + 8xy A) y(2z + 8x) B) 2y(z + 4x) Eliminate C) 2(yz + 4x) D) 4y( 1 2 z + 2x)
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Use the distributive property to factor the expression. 2yz + 8xy A) y(2z + 8x) B) 2y(z + 4x) Eliminate C) 2(yz + 4x) D) 4y( 1 2 z + 2x)
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Use the distributive property to factor the expression. 2yz + 8xy A) y(2z + 8x) B) 2y(z + 4x) Eliminate C) 2(yz + 4x) D) 4y( 1 2 z + 2x)
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NielsK
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The answer is B) 2y(z+4x). The 2y multiples with the z which equals 2yz, then the 2 multiples with the 4x which gives you 8xy. This leaves you with your expression 2yz + 8xy
Adam Neal
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