Question

Find the slope trough (-22,3) and (11,-3)

Answer 1

The slope is
`-(2)/(11)`

Explanation:

Let
`(x_1,y_1)=(-22,3)` and
`(x_2,y_2)=(11,-3)`

The slope is given by;

`m=(y_2-y_1)/(x_2-x_1)`

We plug in the values to get;

`m=(-3-3)/(11--22)`

Simplify;

`m=(-6)/(33)`

`m=-(2)/(11)`

Answer 2

`m=(-2)/(11)` is the slope through the points.

Explanation:

We have given two points:

(-22,3) and (11,-3)

We have to find the slope through (-22,3) and (11,-3).

As we know that

slope = m =
`(y_(2)-y_(1))/(x_(2)-x_(1) )`

Where (x₁,y₁) = (-22,3) , (x₂,y₂) = (11,-3)

Put this values in slope equation we get,

`slope = (-3-3)/(11+22) =(-6)/(33)`

`m=(-2)/(11)`

`m=(-2)/(11)` is the slope through the points.