Please Help ASAP!! 20 points!!

Question

asked Jul 21, 2020 223k views

1 Answer

Cross · Answer 1 · 2020-07-24T21:35:56+0000

Answer:

$\cos ^(-1)((6.3)/(9.8))$

$\sin^(-1) ((7.5)/(9.8))$

Explanation:

Recall and use the mnemonics SOH to obtain;

$\sin(\angle ABC) =(Opposite)/(Hypotenuse)$

This implies that;

$\sin(m \angle ABC) =(7.5)/(9.8)$

Take the inverse sine of both sides to get;

$m\angle ABC =\sin^(-1) ((7.5)/(9.8))$

Also,

$\cos (m\angle ABC)=(Adjacent)/(Hypotenuse)$

$\cos (m\angle ABC)=(6.3)/(9.8)$

$\Rightarrow m\angle ABC=\cos ^(-1)((6.3)/(9.8))$