asked 61.2k views
1 vote
Determine where the real zeros of f(x)=x^4-2x^3+x-2 are located.

a.
at -1 & 2
c.
at 0 & 1
b.
at 1 & 2
d.
at -1 & 1

1 Answer

4 votes

Answer:

a. at -1 & 2

Explanation:

The given function is


f(x)=x^4-2x^3+x-2.

Equate the function to zero.


x^4-2x^3+x-2=0.

Factor by grouping;


x^3(x-2)+1(x-2)=0

Factor further;


(x-2)(x^3+1)=0

Apply the zero product property;


(x-2)=0,(x^3+1)=0

Solve for x;


x=2,x^3=-1


\Rightarrow x=2,x=\sqrt[3]{-1}


\therefore x=2,x=-1

answered
User Osama Qarem
by
8.7k points

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