Question

How many moles of no2 are equivalent to 74.3g of no2

Answer 1

Answer: The number of moles of
`NO_2` in 74.3 g of
`NO_2` is 1.62 moles.

Step-by-step explanation:

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

Given :

Mass of
`NO_2`= 74.3 g

Molar mass of
`NO_2` = 46 g/mol

Putting in the values, we get:

`\text{Number of moles of}NO_2=(74.3g)/(46g/mol)=1.62moles`

Thus the number of moles of
`NO_2` in 74.3 g of
`NO_2` is 1.62 moles.

Answer 2

Answer;

= 1.615 moles

Explanation;

The molar mass of NO2

= 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

= 74.3 g/ 46.01 g/mol

= 1.615 moles