What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in a. 150 in squared b. 197 in squared c. 127 in squared d. 210 in squared

Question

asked Nov 25, 2020 212k views

2 Answers

Timclutton · Answer 1 · 2020-12-02T02:00:20+0000

ANSWER

$197 {in}^(2)$

EXPLANATION

The area of the two tra-pezoidal faces

$= 2 * (1)/(2) * (9 + 5) * 5 = 70 {in}^(2)$

The area of the 5 by 6.4 rectangular face

$= 6.4 * 5 = 32 {in}^(2)$

The area of the two square faces

$= 2(5 * 5) = 50 {in}^(2)$

The area of the 9 by 5 rectangular face is

$= 9 * 5 = 45 {in}^(2)$

The surface area of the design is:

$70 + 32 + 50 + 45=197 {in}^(2)$