Question

Vertex & x and y intercepts of f(x)=x^2

Answer 1

vertex (0, 0)

x-intercept: 0

y-intercept: 0

Explanation:

The vertex form of a quadratic function:

`f(x)=a(x-h)^2+k`

(h, k) - vertex

We have

`f(x)=x^2=1(x-0)^2+0`

Therefore the vertex is in (0, 0).

The x-intercept for y = 0. Substitute:

`x^2=0\to x=0`

The y-intercept for x = 0. Substitute:

`y=0^2\to y=0`