Question

You have 25.0mL HCl of unknown concentration. It takes 12.5 mL of 0.2 M NaOH to neutralize the acid. Determine the concentration of HCl in the following steps.

Which data table would you use to organize the information correctly?

Answer 1

1) The concentration of HCl = 0.1 M.

2) The table that can be used to organize the information correctly is C.

Step-by-step explanation:

1) The concentration of HCl:

• We know that the no. of millimoles of the acid is equal to the no. of millimoles of the base at the neutralization point.

which means that: (MV)HCl = (MV)NaOH,

M of HCl = ??? M, V of HCl = 25.0 mL.

M of NaOH = 0.2 M, V of NaOH = 12.5 mL.

∴ M of HCl = (MV)NaOH/V of HCl = (0.2 M)(12.5 mL)/(25.0 mL) = 0.1 M.

2) The table that can be used to organize the information correctly is C

Table A and B are the same and reported volume of HCl and NaOH is wrong.

Table C is right, contain the correct volumes and concentration of NaOH and missed the concentration of HCl which is 0.1 M.

Table D reported the volume and the concentration of HCl wrongly and also the concentration of NaOH. The data reported of HCl and NaOH is reversed.